Question: Multiplying two integers, a and b, is actually done by adding the first number, a, to itself b times. Dividing two numbers, a/b, is likewise
Multiplying two integers, a and b, is actually done by adding the first number, a, to itself b times.
Dividing two numbers, a/b, is likewise actually done by subtracting the second number, b, from the first number, a, repeatedly until a is smaller than b (this is the remainder). The number of subtractions done is the number of times b goes into a.
Write two iterative methods, one for multiplication by addition and one for division by subtraction.
Write a recursive method that will multiply two numbers by adding the first to itself this way.
Write a second recursive method that will divide two numbers this way.
After testing all methods for accuracy, run the two multiply methods repeatedly, increasing the factors by a factor of ten until your program experiences failure. Quit running the method that failed, but continue running the method that did not fail, still increasing the factors by a power of ten until it, too, fails
Submit your code, and a written report discussing and detailing how each of the methods failed (what were the symptoms of failure) and what actually caused their failure.
Partial Pseudo-code:
In main
Create a loop so you can call your recursive and iterative methods lots of times and get a better picture of the performance difference.
Write a small driver that tests each of the four methods (exhaustively)
After testing, run a loop that
prompts for either the two multiply or the two divide methods
prompts for two integers
runs the selected methods
a * b
In multiply (recursive)
if a or b is zero
return zero
else
subtract 1 from b
return a + (multiply with new parameters)
a/b
In divide (recursive)
If b is zero, throw an exception
if a is less than b
return 0
else
subtract b from a
return 1 + (divide with new parameters)
** I have everything else i just need help with what is in bold **
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