my task is to find the key phrase that will defuse the bomb within the disassembly code. Here is the code disassembly: Dump of assembler code for function phase$\_3$:

$0$x$0000000000400$f$54<+0>$: sub $$0$x$18,\%$rsp

$0$x$0000000000400$f$58<+4>$: lea $0$x$8(\%$rsp$),\%$rcx

$0$x$0000000000400$f$5$d $<+9>$: lea $0$xc$(\%$rsp$),\%$rdx

$0$x$0000000000400$f$62<+14>$: mov $$0$x$402785,\%$esi

$0$x$0000000000400$f$67<+19>$: mov $$0$x$0,\%$eax

$0$x$0000000000400$f$6$c $<+24>$: callq $0$x$400$c$30<\_\_$isoc$99\_$sscanf@plt$>$

$0$x$0000000000400$f$71<+29>$: cmp $$0$x$1,\%$eax

$0$x$0000000000400$f$74<+32>$: jle $0$x$400$f$88$

$0$x$0000000000400$f$76<+34>$: cmpl $$0$x$7,0$xc$(\%$rsp$)$

$0$x$0000000000400$f$7$b $<+39>$: ja $0$x$400$fc$0$

$0$x$0000000000400$f$7$d $<+41>$: mov $0$xc$(\%$rsp$),\%$eax

$0$x$0000000000400$f$81<+45>$: jmpq $*0$x$4024$e$0(,\%$rax,$8)$

$0$x$0000000000400$f$88<+52>$: callq $0$x$401549$

$0$x$0000000000400$f$8$d $<+57>$: jmp $0$x$400$f$76$

$0$x$0000000000400$f$8$f $<+59>$: mov $$0$x$199,\%$eax

$0$x$0000000000400$f$94<+64>$: jmp $0$x$400$fd$1$

$0$x$0000000000400$f$96<+66>$: mov $$0$x$3$a$0,\%$eax

$0$x$0000000000400$f$9$b $<+71>$: jmp $0$x$400$fd$1$

$0$x$0000000000400$f$9$d $<+73>$: mov $$0$x$345,\%$eax

$0$x$0000000000400$fa$2<+78>$: jmp $0$x$400$fd$1$

$0$x$0000000000400$fa$4<+80>$: mov $$0$x$7$a$,\%$eax

$0$x$0000000000400$fa$9<+85>$: jmp $0$x$400$fd$1$

$0$x$0000000000400$fab $<+87>$: mov $$0$x$2$ba$,\%$eax

$0$x$0000000000400$fb$0<+92>$: jmp $0$x$400$fd$1$

$0$x$0000000000400$fb$2<+94>$: mov $$0$x$185,\%$eax

$0$x$0000000000400$fb$7<+99>$: jmp $0$x$400$fd$1$

$0$x$0000000000400$fb$9<+101>$: mov $$0$x$311,\%$eax

$0$x$0000000000400$fbe $<+106>$: jmp $0$x$400$fd$1$

$0$x$0000000000400$fc$0<+108>$: callq $0$x$401549$

$0$x$0000000000400$fc$5<+113>$: mov $$0$x$0,\%$eax

$0$x$0000000000400$fca $<+118>$: jmp $0$x$400$fd$1$

$0$x$0000000000400$fcc $<+120>$: mov $$0$xc$9,\%$eax

$0$x$0000000000400$fd$1<+125>$: cmp $\%$eax,$0$x$8(\%$rsp$)$

$0$x$0000000000400$fd$5<+129>$: jne $0$x$400$fdc

$0$x$0000000000400$fd$7<+131>$: add $$0$x$18,\%$rsp

$0$x$0000000000400$fdb $<+135>$: retq

$0$x$0000000000400$fdc $<+136>$: callq $0$x$401549$

$0$x$0000000000400$fe$1<+141>$: jmp $0$x$400$fd$7$

End of assembler dump. This is what i know so far:

The return value of $\_\_$isoc$99\_$sscanf must be greater than $1,$ indicating that two integers were successfully scanned.

The second integer $(0$xc$(\%$rsp$))$ must be less than or equal to $7.$

The address jumped to based on the value of the second integer must lead to the address range $0$x$0000000000400$f$8$f $<+59>$ to $0$x$0000000000400$fbe $<+106>,$ inclusive.

These conditions ensure that the bomb does not explode. The input format should be two integers separated by a space, where the first integer is $3.$ can you heldp me find the phrase I need to denote?