$NH3-$ air mixture containing $5\%NH3$ is scrubbed with water to remove $NH3,5000k\frac{g}{h}r$ of

gas mixture is to be processed with $2,00,000k\frac{g}{h}r$ of water to reduce $NH3$ in the exit gas to

$0\mathrm{.}15\%.$ Calculate the height of packing required assuming dilute solutions are involved.

Equilibrium relation is given by $Y=20x$ where $x,Y=$ mole fraction of $NH3$ in liquid and

vapor. HTU$=2m$

SO$2-$air mixture containing $8\%SO2$ at $20C$ and $1$atm is to be scrubbed with water in a sieve

plate column. The air and water flow rate is $32\mathrm{.}6k\frac{g}{m}2$ s$.$ If $95\%$ of $SO2$ is to be recovered.

Calculate the number of theoretical trays required. Equilibrium Data at $20C$ and $1$atm :

It is desired to absorb $95\%$ ammonia from a feed mixture contain $10\%$ ammonia and rest air.

The gas enters at rate of $500$kmo$\frac{l}{h}r.$ if water is used as solvent at the rate of $1\mathrm{.}5$ times of the

minimum calculate $($a$)$ NTU $($b$)$ Ls actual $($c$)$ height of the tower if HTU$=1m$ the equilibrium

relationship is given by $Y=20x$

A packed tower is designed to recover $98\%CO2$ from gas mixture contain $10\%CO2$ and

$90\%$ air using water. The equilibrium relation is $Y=14x$ where $Y$ is kgCO$\frac{2}{k}g$ dry air. And

$x$ is kgCO$\frac{2}{k}g$ water. The water to gas ratio is kept at $30\%$ more than the minimum value.

Calculate height of tower if HTU is $1\mathrm{.}25m.$

A packed tower is used to remove $96\%SO2$ from a stream of air containing $0\mathrm{.}0291$ mole

fraction $SO2.$ The $SO2$ is removed by absorbing it in water which enters the tower with a

mass velocity of $0\mathrm{.}51$kmo$\frac{l}{m}2s$ and the gas stream enters the tower counter currently at the

mass velocity of $9\mathrm{.}7510-3$kmo$\frac{l}{m}2s.$ Determine the packed tower height. The following

data are available. Kxa$=0\mathrm{.}94$kmo$\frac{l}{m}3s,$Kya$=0\mathrm{.}0496$kmo$\frac{l}{m}3s.$ Slope of the equilibrium

line $=28\mathrm{.}7$