Need help with step 6 please

Step 5 The area of the given figure having the vertices (0, 0), (1, 5), (3, -2) and (1, -6) is A = 5xax + - 6xax + ( ( - z x + 1 7 ) ax + / ( 2x - 8 ) dx . By interchanging the limits of x for the integrals, and (2x - 8)dx - - (1 ~ [ 2 x - 8) dx Therefore, A = [5x - (-6x)] dx + /3( - zx+ 17) - (2x - 7, ox 11 x dx + -11/2 - 5.5 > + 33/2 16.5 dx } 11 11 71 + -11/4 -2.75 X2 + 33/2 V 16.5 2 Step 6 Apply the fundamental theorem of calculus, which states that / f(x) dx = F(b) - F(a). A= 11 2 + 49.5 + 2.75 - 16.5