Question: need to find out answer by formula given below A B C D E F G H K L M N 0 P Q Q

need to find out answer by formula given below A

need to find out answer by formula given below

need to find out answer by formula given below A

A B C D E F G H K L M N 0 P Q Q R S ES EF 6 7 8 A= 3 9 10 LS LF C = 12 F = 6 11 G= 8 Start 12 13 | = 3 End B = 6 14 15 D = 5 E=4 H = 7 16 17 18 19 20 21 INSTRUCTIONS 22 1 IRENAME THE FILE WITH YOUR STUDENT NO AND STUDENT NAME. FAILURE TO DO THIS, WILL RESULT IN A 0.5 MARK DEDUCTION. 23 2 PUT YOUR STUDENT NO AND STUDENT NAME ON TOP OF THIS PAPER. FAILURE TO DO THIS WILL RESULTIN 0.5 MARK DEDUCTION. 24 3 EARLY START = 1 25 QUESTION 26 CALCULATE THE FORWARD PASS AND BACKWARD PASS OF EACH ACTIVITY IN THE PROJECT SCHEDULE. IN THE TABLE BELOW, HIGHLIGHT THE ACTIVITIES ON THE CRITICAL PATH, 27 BY HIGHLIGHTING IN YELLOW. FAILURE TO DO THIS, WILL RESULTINA 1 MARK DEDUCTION. 28 MARK ALLOCATION 29 1 identication of the critical path 0.5 30 2 Calculation of the ES, EF, LS, LF 36 0.125 4.5 31 5 32 22 1. Find out the total values of all the paths. 2. The path with the highest value is the critical path. Labels ES D EF Task a. Early Start = ES b. Early Finish = EF C. Late Start = LS d. Late Finish = LF LS S LF Formulas & Rules For the FORWARD PASS: Mainly concerned with the Early Start and Finish. i. ES = 0 or 1, unless mentioned otherwise. EF = ES+D-1 1. First find the Early Start and early Finish on the Critical Path using the formulas above. 2. To find the Early Start and Early Finish of an Activity. a. ES(Successor) = EF(Predecessor) + 1 b. EF(Successor) = ES(Successor) + D-1 3. For a successor, if it has multiple predecessors, then use the Early Finish of the predecessor with the largest value. For the BACKWARD PASS: Mainly concerned with the Late Start and Finish. i. LF (last activity) = EF (last activity) ii. LS (last activity) = LF (last activity) - D + 1 1. First find the Late Finish and Late Start on the Critical Part using the formulas above. 2. To find the Late Finish and Late Start of the predecessor activity, use: a. b. LF (predecessor activity) = LS (successor activity or last activity) - 1 LS (predecessor activity) = LF (predecessor activity) - D + 1 3. For a predecessor, if it has multiple successors, then use the Late Start with the lowest value

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