needed asap ,pleaee

Consider the following scenario. Activity Predecessor Normal Crashing Normal Crashing Time Time Cost cost (S) (days) (day) (5) 230 10 9 350 B. 8 7 425 SOO C 12 10 250 500 B 2 500 680 9 8 700 750 E DE 3 2 650 880 The Crashing Cost/Activity for activiry "E" is 3 points None of the answers. $57 $75 $50 $100 The "number of activity crashing" for activity "A" is 3 points 0 1 week O 1 month 0 1 day 0 1 hour O None of the answers. The project completion time is with a normal cost of 3 points O 34 days; $2,775 21 days; $3,025 O 19 weeks; $4,025 O 31 days; $2,775 None of the answers. To crush the project by day we cheese activity..... at an additional crashing cast of 3 points ODS75 None of the answers E: $50 O A $100 O c $25 The new project cost" is equal to 3 points $2,200 $2,075 None of the answers $2,825 $2,175 To crash the project by an additional day, we choose activity..... at an additional 3 points crashing cost of O c; $75 OB: 850 OD: $100 O A $100 O None of the answers. The resuleing project costi 3 points $2,925 O $2,200 O $2,275 $2,225 None of the answers Crashing the project twice results in 3 points two alternative critical paths which are "A-D-E&A-C-E O one critical path "A-C-E-F O two alternative critical paths which are "A-B-D-E&A-C-E one critical path A-B-D-E None of the answers. To crash the project by a third day we choose ar an additional cost of 3 points O A&C. 175 O None of the answers. OC, $125 O E $80 O A $100 The resulting project completion cost after the ind crashing is 3 ports $5,575 None of the answers $6,275 $3,050 84.275