Not allow

1.loop

2.try except

def is_a_number (s:str)-> bool: Returns True if and only if s is a string representing a positive number. Examples: is a number() True /is a number("One" ) False eis aumber-3 Talse >>> is-a-number("3.") True 8 is a number("3.1.2") Fals #Your code goes here .:print(is-a-number("1")) #True ., print (is-a-number("15")) #True .: print(is-a-number("60")) #True print (is-a number("One")) #False .) print (is-a number("-3")) #False Print (is-a-number("-17")) #False print(is-a-number(-3.")) #True eprint(is a number("10.12")) #True .,print ( isa-number("3.1.2")) #False .Print(is-a-number(-10.1.4")) #False .) print (is-a number("10m/ s")) #False