Question: Now we have: a +6 + c = d Where (a, b, c, d e Z+) Given the following assertions: P: d is even R:

 Now we have: a +6 + c = d Where (a,

Now we have: a +6 + c = d Where (a, b, c, d e Z+) Given the following assertions: P: d is even R: a,b,c are all even. Use a proof by cases to show P HR Note: An odd number equals 2m + 1 for some integer m, so its square equals 4(m2 + m) + 1

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