nsider this reaction:

$2N{H}_3(g)N_2(g)+3H_2(g)$

At a certain temperature it obeys this rate law.

rate $=(0\mathrm{.}0306s^{-1})[N{H}_3]$

Suppose a vessel contains $N{H}_3$ at a concentration of $0\mathrm{.}160M.$ Calculate the concentration of $N{H}_3$ in the vessel $29\mathrm{.}0$ seconds later. You may assume no other

reaction is important.

Round your answer to $2$ significant digits.