Ogden Strain energy function is given as:

$=({}_1+{}_2+{}_3)={\displaystyle \underset{p=1}{\overset{N}{}}}\frac{{}_p}{{}_p}({}_1^{{}_p}+{}_2^{{}_p}+{}_3^{{}_p}-3)$

The values of these constants for a rubber material are given as follows:

${}_1=1\mathrm{.}3$

${}_2=5\mathrm{.}0$

${}_3=-2$

${}_1=6\mathrm{.}3**{10}^5\frac{N}{m^2}$

${}_2=0\mathrm{.}012**{10}^5\frac{N}{m^2}$

${}_3=-0\mathrm{.}1**{10}^5\frac{N}{m^2}$

And shear modulus is $=4\mathrm{.}225**{10}^5\frac{N}{m^2}$

Plot first PK stress, second PK stress, and Cauchy Stress versus strain up to strain value of $6\mathrm{.}0,$ i$.$e$.,600\%$ strain for uniaxial loading. There is no change in volume during the deformation. However, you may ignore the hydrostatic pressure for incompressible material for simplicity. The more point will predict better fit, however, use at least $20$ points for the strain range of $0-6\mathrm{.}0.$

Feel free to use Python$/$Matlab$/$ or excel to plot, however, submit your hand calculations deriving the equations you are plotting.$|$