Ok now can you help me answer the last three questions

where T is the period in seconds, m is the mass in kg, and k is the spring constant in Newtons per meter that you calculated above. Use this equation to answer the following questions: a. How does the period T relate to the mass of the spring? The period increases with the square root of the mass because as the period increases the so does the mass. This equals to slower oscillations and creates a longer period. b. How does the period T relate to the spring constant k? Oscillations happen faster because the stiffer spring creates a shorter period. So the period decreases as the spring constant increases. c. If I gave you a stiffer spring (this means a higher spring constant) what would happen to the period of oscillation? The period would decrease because the spring is harder to stretch which makes the motion become faster. d . How does the distance you raise the spring (Ax) relate to the affect the period? Where is it in the equation? The stretch distance in the spring isn't in the equation so it doesn't affect the period. The period doesn't depend on how far you stretch the spring for small oscillations. Calculate the theoretical period for your trial (the one with just the cart hanging - not the extra mass). Calculate the percent differences between the theoretical period and the actual period. 29. If this is inaccurate, explain why... or better yet see if you can fix it! You should get good data from this experiment