On the basis of stoicheometry, justify the answer why 1 mL of 0.025 M of Na2S2O3 is
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On the basis of stoicheometry, justify the answer why 1 mL of 0.025 M of Na2S2O3 is equivalent to 1.0 mg/L of DO? Calculate the DO value if your 250 mL sample consumes 18 mL of 0.014 M Na2S2O3?
Related Book For
Intermediate Accounting
ISBN: 978-0324592375
17th Edition
Authors: James D. Stice, Earl K. Stice, Fred Skousen
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