onsider a system built on a $48$ MHz processor with a main loop and an interrupt which occurs at a $10$ kHz frequency. Assume the ISR take $14\mathrm{.}9$ us to execute and there is a total of $1$ us of response and return time overhead.

What percentage of the processor$$s time is spent in interrupt response and return overhead?

What percentage of the processor$$s time is left for the main loop to execute?

If the main loop requires $37$ ms of computation to execute one iteration, what is the minimum main loop update rate $($in Hz$)?$

Consider the system above again, but now with the interrupt running at $25$ kHz and the ISR taking $34$ us to execute.

What percentage of the processor$$s time is spent in interrupt response and return overhead?

What percentage of the processor$$s time is left for the main loop to execute?

If the main loop requires $37$ ms of computation to execute one iteration, what is the minimum main loop update rate $($in Hz$)?$