Over what interval on the graph shown could the Intermediate Value Theorem (IVT) apply? O everywhere 0 (1 ,1) [1,-0.5] 0 [-1,1] Over what interval on the graph shown will the Intermediate Value Theorem (IVT) apply? 0 Everywhere 0 [2, 8] O [2, 2.99999] 0 [3, 8] 0|. cu 2 Use the NT to show that f(X) = X 3 has a zero in the interval [-4,4]. f(x) is continuous on [4,4], f(-1)= -2, f(4) = 13, so we can use the NT to show there is a zero, between [-1,4]. O f(x) is continuous on [-4,4], f(-1)= -2, f(0) = -3, so we can use the NT to show there is a zero, between [-1,0]. O The IVT cannot be applied to find a zero. O f(x) is continuous on [-4,4], f(-4)= 13, f(4) = 13, so we can not use the NT to show there is a zero