Part B Two point charges 91 = +2.50nC and q2 = 6.25nC are 0.100 m apart. Point A is midway between them; point B is 0.080 m from 91 and 0.060 m from 92. (See (Figure 1).) Take the electric potential to be zero at infinity. Find the potential at point B. Express your answer in volts. V = -660 V Figure 91 -0.080 m B 0.060 m -0.050 m0.050 A Submit Previous Answers Correct Part C Find the work done by the electric field on a charge of 2.80 nC that travels from point B to point A. Express your answer in joules to two significant figures. W = 1 of 1 Submit Previous Answers Request Answer ? Incorrect; Try Again; 4 attempts remaining m 92 Provide Feedback J A charge of 27.0 nC is placed in a uniform electric field that is directed vertically upward and that has a magnitude of 4.00104 N/C. What work is done by the electric force when the charge moves You may want to review (Page). For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Work in a uniform electric field. Part B 0.620 m upward; W = 6.7010-4 J Submit Previous Answers Part C Correct F is upward and 3 is upward, so = 0. W = Fs=qEs = (2.70 108C)(4.00 10N/C) (0.620m) = 6.70 2.80 m at an angle of 45.0 downward from the horizontal? W = Submit Previous Answers Request Answer Incorrect; Try Again; 5 attempts remaining ? J