Question: Part D and E please P2-4(a) Revisit Examples 2-1 through 2-3. How would your answers change if the flow rate, Fao, were cut in half?

Part D and E please  Part D and E please P2-4(a) Revisit Examples 2-1 through 2-3.
How would your answers change if the flow rate, Fao, were cut

P2-4(a) Revisit Examples 2-1 through 2-3. How would your answers change if the flow rate, Fao, were cut in half? If it were doubled? (b) Example 2-5. How would your answers change if the two CSTRs (one 0.82 m and the other 3.2 m) were placed in parallel with the flow, Fo, divided equally between the reactors? (c) Example 2-6. How would your answer change if the PFRs were placed in parallel with the flow, Fao, divided equally to each reactor? (d) Example 2-7. (1) What would be the reactor volumes if the two interme- diate conversions were changed to 20% and 50%, respectively? (2) What would be the conversions, X, X2, and X3, if all the reactors had the same volume of 100 dm and were placed in the same order? (3) What is the worst possible way to arrange the two CSTRs and one PFR? (e) Example 2-8. The space time required to achieve 80% conversion in a CSTR is 5 h. The entering volumetric flow rate and concentration of reactant A are 1 dm /min and 2.5 molar, respectively. If possible, deter- mine (1) the rate of reaction, -"A = (2) the reactor volume, V = (3) the exit concentration of A, CA = and (4) the PFR space time for 80% conversion. Example 2-7 An Adiabatic Liquid-Phase Isomerization The isomerization of butane n -CH 2 -CH10 was carried out adiabatically in the liquid phase and the data in Table E2-7.1 were obtained. (Example 8.4 shows how the data in Table E2-7.1 were generated.) TARLA E2-7.1 RAW DATA X 0.0 0.2 0.4 0.6 0.65 - (kmom. h) 39 53 59 38 25 Example 2-8 Reactor Space Times and Space Velocities Calculate the space time, t, and space velocities for each of the reactors in Exam- ples 2-2 and 2-3. Solution From Example 2-1, we recall the entering volumetric flow rate was given as 2 dm's (0.002 m/s), and we calculated the concentration and molar flow rates for the conditions given to be no = 0.2 mol/dm and Fro = 0.4 mol/s. From Example 2-2, the CSTR volume was 6,4 m and the corresponding space time and space velocity are V 6.4 m 3200 s =0.89 h U 0.002 m/s SV 1.125 h 0.89 h From Example 2-3, the PFR volume was 2.165 m, and the corresponding space time and space velocity are V - 2.165 m 1083 s=0.30 h V, 0.002 m/s

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