PbS$($s$)+2$HBr$($aq$)----$PbBr$($s$)+$ H$2$S$($g$)$

If $10\mathrm{.}7$g PbS and $6\mathrm{.}9$g HBr react to make $13\mathrm{.}3$ g PbBr$2,$ how much PbBr$2$ could be made; what's the limiting reactant $($LR$)$; and what is the percent yield?