lear CALCULUS 13 f R (0) R given by f(x) 8 EXERCISE can be made continuous at x 0 by delining u log(3 x) log (3 x) k, the value f0) is If x0 2) 2 3) 1 4) 0 1) JI px of kis if Isr 0 2) 3) 4) 3 1) 0 f(x) 2x 1 if OsxsI is X 2 continuous on 1 1, 1 then p is 2) 3) e 4) e 12 1) (1 cos x)sin 5x 1) 0 2) 1 3) 1 2 4) 12 sin 3x 3 2) 10 10 Observe the following lists List I 10 4) I) 3) then f(x) is A) fx) x x at x Ji cos 2x Ex B) fx) x 0 f(0) 1 X 40 C) fx) Tan(x 2) 2 3) 0 1) 1 4) doesnot exist 2) 1 x 2 and RSI Statement I VA 4x 1 x D) f(x) xCos 0 f(0) 1 X 3 Statement II Li loga log, 6 List II Va 6 3 cos( Sin Statement III x 1 2 1 Tan Sin I Continuous II right continuous then f(x) ut x 0 is III Left continuous f( 2) 1, then at x 2, f(x) is Which of the above is are correct IV Discontinuous then f(x) at x 0 is 1) only 1, II 3) 1, II, II 2) only II, II 4) only 1 II The value of f at x 0 so that the function The correct match is A D A B II IV 2)I C D III IV I) I II II 2 2 (x0) is continuous 3) IV III II I 4) IV II III 1 at x 0 is 11 f(x) COSX sin x cos 2x is continuous af 4 I) log 4 2) e4 3) log 2 4) 0 72 94 8 1 Let f(x) 2 cosx then 4 3D klog 2 log 3 If f is continuous function at x 0, then k x 0 E 3) J2 4) VE 2) 24 12 If f R R is continuous such that f(r y 3)185 4) 242 f(x) f(y) V X, y e R and f(1) 2, then f(100) 1) 100 104 2) 101 31 200

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Question: lear CALCULUS 13 f: R- (0) R given by f(x) = 8. EXERCISE - can be made continuous at x = 0 by delining

lear CALCULUS 13 f: R- (0) R given by f(x) = 8.

lear CALCULUS 13 f: R- (0) R given by f(x) = 8. EXERCISE - can be made continuous at x = 0 by delining u log(3+x)- log (3-x)-k, the value f0) is If x0 2) 2 3) -1 4) 0 1) ! - JI- px of kis if -Isr

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