please answer all my teacher didnt explain so im a little lost on it.

i need someone to answer the problems so I can better understand the problems.

G0AL Apply Coulomby law in two dimensions. PROBLEM Consider three point charges at the corners of a triangle, as shown in Figure 15.8, where q1=6.00107C, h1=2.00109C, and 3=5.00109C. (a) Find the components of the force F21 exerted by q2 on q1 (b) Find the componens of the force F1 exerted by q1 on qy (c) Find the resultant force on q, in terms of composents and also in terms of magnitude and direction. 5TRATEGY Coulomb' law gives the magnitude of each force, which ean be split with right-crangle trigonometry into x-and Jcomponens, Sum the veciors componentwise and then find the magnaitude and direction of the reaultant vector. Figure 15.8 (Example 15.3) The force carricd by q1 of q9 is eicried on q3 is the widernum F1s+Vi SOLUTION (a) Find the components of the force exeried by q2 on q9 : Find the magnitude of Fas with Coulomb's law: F23Fis=kr2qaa=(8.99100Nm2/C2)(4.00m)2(2.00109C)(5.00109C)=5.62109N Because F21 is horizontal and points in the negative xedirection, the negative of the magnitude gives the *-component, and the y-component is zero: (b) Find the components of the force exeried by q1 on q9 : Find the magnitude of F19 : F1sF1s=k2r2qtqs=(8.9910Nm2/C3)(5.00m)2(6.00109C)(5.00100C)=1.08101N Use the given triangle to find the components of ris: : F136F13y=F13cos=(1.08108N)cos(36.92)=8.64109N=F19sin=(1.08102N)sin(36.9)=6.48109N (c) Find the components of the resultant vector. Sum the scomponents to find the resultant F;; FV=5.62109N+8.64109N=3.02109N Sum the y-components to find the resultant Fy. F=0+6.48109N=6.48109N Find the magnitude of the resultant ferce on the charge qp using the Pythagorean theoreme =(3.01101N)2+(6.50107N)2=7.15109N Fiad the angle the resultant force makes with respect. to the positive saxis: =tan1(F2F1)=tan1(3.02101N648109N)=