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1.14 [20/20/15] When making changes to optimize part of a processor, it is often the case that speeding up one type of instruction comes at the cost of slowing down something else. For example, if we put in a complicated fast floating-point unit, that takes space, and something might have to be moved farther away from the middle to accommodate it, adding an extra cycle in delay to reach that unit. The basic Amdahl's Law equation does not take into account this trade-off. 20 speedup (ignoring the penalty to any other instructions)? 20 Now assume hat speeding up he floating point unit s owed down data cache accesses, resulting in a 1.5x slowdown or 2/3 speedup. Data cache accesses consume 10% o time. What is the overall speedup now? the new fast floating-point unit speeds up floating point operations by, on average, 2 and floating point operations take 20% of the original program's execution time, what is the overall a b he execution c. [151