Please confirm the answer for question $3$ and the rest of the question. I need an expert tutor to look over my solution

You are a newsvendor selling the San Pedro Times every morning. Before you get to work, you go to the printer and buy the day$$s paper for $$0\mathrm{.}50$ a copy. You sell a copy of the San Pedro Times for $$2\mathrm{.}50.$ Daily demand is distributed normally with mean $=300$ and standard deviation $=50.$ At the end of each morning, any leftover copies are worthless and they go to a recycle bin. According to the above information, answer the following six questions.

Please confirm my answer and make adjustment also complete

Question $1$

Determine the underage cost. Keep two decimals.

selling price $-$ procurement$/$manufacturing cost

$$2\mathrm{.}50-\mathrm{.}50=2\mathrm{.}00$

Question $2$

Determine the critical ratio. Keep two decimals.

Cost of overage$($Co$)=$ Cost price $-$ salvage value $=0\mathrm{.}5-0=0\mathrm{.}5$

Cu$/$Cu$+$Co$=2\mathrm{.}00/2\mathrm{.}00+\mathrm{.}50.=0\mathrm{.}80$ or $80\%$

Question $3$

Determine the optimal order quantity. Round your answer to the nearest integer.

FORMULA FOR $($EOQ$)$

Q$*=$SQR$(2$KD$)/$H

please answer this question?

Question $4$

Everything else being equal, which of the following will lead to increased optimal order quantity?

Increase the cost of the paper from $$0\mathrm{.}50$ to $$0\mathrm{.}60.$

Reduce the selling price from $$2\mathrm{.}50$ to $$2\mathrm{.}20.$

Increase the standard deviation of demand from $50$ to $60.$

Reduce the mean of the demand from $300$ to $250.$

Question $5$

Suppose you want to find the order quantity that ensures a $95\%$ in$-$stock probability, determine the order quantity. Round your answer to the nearest integer.

To find the order quantity that ensures a $95\%$ in$-$stock probability, we need to find the demand level at which the probability of demand being less than or equal to that level is $0\mathrm{.}95.$ For a normal distribution, this is the mean plus the standard deviation times the z$-$score corresponding to $0\mathrm{.}95.$

The z$-$score for a probability of $0\mathrm{.}95$ is approximately $1\mathrm{.}645.$ So$,$ the order quantity is:

Order Quantity $=$ Mean $+$ Z $*$ Standard Deviation

Q $=\backslash$mu $+$ z $\backslash$times $\backslash$sigma $=$

$=300+1\mathrm{.}645*50$

$=382\mathrm{.}25$

ANSWER: $382$

Question $6$

Given order quantity Q$=350,$ calculate the expected profit. Round your final answer to the nearest integer. DO NOT round intermediate results.

$$ Expected lost sale

$$ z $=($Q$-)/\backslash$sigma $=(350-300)/50=1$

WHEN LOOKING AT THE TABLE WE LOOK AT $1$ PLEASE CONFIRM??

$$ L$($z$)=0\mathrm{.}0833$

$$ Expected lost sale $=\backslash$sigma $\backslash$times L$($z$)=50\backslash$times $0\mathrm{.}0833=4\mathrm{.}165$

$$ Expected sales

$$ Expected demand $$ Expected lost sales $=300-4\mathrm{.}165=295\mathrm{.}835$

$$ Expected leftover inventory

$$ Order quantity $$ Expected sales $=350-295\mathrm{.}835=54\mathrm{.}165$

$$ Expected profit

$($Price$-$cost$)\backslash$times Expected Sales $-($Cost$-$Salvage value$)\backslash$times Expected leftover inventory $=(2\mathrm{.}50-\mathrm{.}50)\backslash$times $295\mathrm{.}835-(0\mathrm{.}50-0)\backslash$times $54\mathrm{.}165$

$$564\mathrm{.}5875$

$$565.$ Answer

Please confirm all the Appendix: Standard Normal Loss Function Table $($continued$)$

Standard Normal Loss Function Table, $L(z)($Concluded$)$answers if they are correct and also make adjustment and answer question #$3.$ please verify the answer before they are submitted, questions has been cancelled do to incomplete, thank you