Question: Please convert this C++ code to arm assembly please. The multiplication part is the most important. Thank you. // Multiply with current digit of first
// Multiply with current digit of first number /I and add result to previously stored result lI at current position. int sum-nl*n2+ result[i nl +i_n2]+ carry; lI Carry for next iteration carry-sum/10; // Store result result[i-ni + i-n2] = sum % 10; i n2++ // store carry in next cell if (carry >0) result[i nl i_n2]+ carry; /I To shift position to left after every // multiplication of a digit in num i nl++
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