Question: Please do not change any variables/ method parameters in the code and finish as it is. Please also, create a JUnit test file for the

Please do not change any variables/ method parameters in the code and finish as it is.

Please also, create a JUnit test file for the questions in the main function.

Thanks

import java.util.List; import java.util.function.Function; import java.util.function.BiFunction; import java.util.function.Predicate; import java.util.ArrayList; import java.util.Comparator;

public class fp { static List map(Iterable l, Function f) { return null; }

static V foldLeft(V e, Iterablel, BiFunction f){ return null; }

static V foldRight(V e, Iterablel, BiFunction f){ return null; }

static Iterable filter(Iterable l, Predicate p){ return null; }

static U minVal(Iterable l, Comparator c){ // write using fold. No other loops permitted. return null; }

static > int minPos(Iterable l){ // write using fold. No other loops permitted. return 0; }

public static void main(String[] args) { // (1) Use map to implement the following behavior (described in Python). i.e given a List create a List of the hashes of the objects. // names = ['Mary', 'Isla', 'Sam'] // for i in range(len(names)): // names[i] = hash(names[i]) // (2) Use foldleft to calculate the sum of a list of integers. // i.e write a method: int sum(List l) // (3) Use foldRight to concatenate a list of strings i.e write a method // String s (List l) // (4) consider an array of Persons. Use filter to // print the names of the Persons whose salary is // greater than 100000 // (5) Use minVal to calculate the minimum of a List of // Integers // (6) Use minVal to calculate the maximum of a List of // Integers // (7) Use minPos to calculate the position of the // minimum in a List of Integers

// (8) Use minPos to calculate the position of the

// minimum in a List of String

}

}

class Person{ final int salary; final String name; Person(int salary, String name){ this.salary = salary; this.name = name; } int getSalary() { return salary; } String name() { return name;} }

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