Question: PLEASE DO NOT COPY PASTE FROM CHEGG/OTHERWISE I'LL REPORT YOU OR GIVE OU A DISLIKE {PROBLEM:4) import pandas as pd def funco(df,x): Parameters df: data
PLEASE DO NOT COPY PASTE FROM CHEGG/OTHERWISE I'LL REPORT YOU OR GIVE OU A DISLIKE
{PROBLEM:4) import pandas as pd def funco(df,x): Parameters df: data frame x: int, float An integer or float Returns series A series with the same index as the data frame 'df, containing the elements of the first column of "df, multiplied by 'X'.df.iloc[:, 0) = x * df.iloc[:, o return df.iloc[:, Oj def funci(df,x): Parameters df: data frame X: int, float An integer or float Returns ------- data frame A data with the same structure as df (that is, same index and columns) but with the elements in the first column replaced with:
+ (x*
) where
' stands for the original elements in the first column of 'df For instance, if all the elements of the original data frame are 1, then funci(df, x=2) will return a data frame with all elements in the first column equal to 3. # Create a series with the elements of the first column of 'x' multiplied # by 'x' ser = funco(df, x) # Then add the elements in the original first column to this series df.iloc[:, ] = df.iloc[:O] + ser # Then return the modified data frame return df {PROBLEM:4) import pandas as pd def funco(df,x): Parameters df: data frame x: int, float An integer or float Returns series A series with the same index as the data frame 'df, containing the elements of the first column of "df, multiplied by 'X'.df.iloc[:, 0) = x * df.iloc[:, o return df.iloc[:, Oj def funci(df,x): Parameters df: data frame X: int, float An integer or float Returns ------- data frame A data with the same structure as df (that is, same index and columns) but with the elements in the first column replaced with:
+ (x*
) where
' stands for the original elements in the first column of 'df For instance, if all the elements of the original data frame are 1, then funci(df, x=2) will return a data frame with all elements in the first column equal to 3. # Create a series with the elements of the first column of 'x' multiplied # by 'x' ser = funco(df, x) # Then add the elements in the original first column to this series df.iloc[:, ] = df.iloc[:O] + ser # Then return the modified data frame return df
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