Question: Please help explain how to setup Qgained = Qlost equation I am struggling with what numbers go where and how the latent heat factors in
Please help explain how to setup Qgained = Qlost equation I am struggling with what numbers go where and how the latent heat factors in as well

5. A 680 g piece of copper is heated in a furnace to a temperature 7. The copper is then inserted into a 175 g copper calorimeter containing 2:75 g of water. The initial temperature of the water and calorimeter is 20 .C, and the final temperature after equilibrium is established is 36 C. When the calorimeter and its contents are weighed, 40.0 g of water are found to have evaporated. What was the temperature T?(Cw = 4186 J/(kg. C), LF=3.35 x 10 J/kg, Ly=2.26 x 106 J/kg, Ccopper = 387 J/(kg. C)
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