Please help

\fA study compared three display panels used by air traffic controllers. Each display panel was tested for four different simulated emergency conditions. Twenty-four highly trained air traffic controllers were used in the study. Two controllers were randomly assigned to each display panel-emergency condition combination. The time (in seconds) required to stabilize the emergency condition was recorded. The following table gives the resulting data and the JMP output of a two-way ANOVA of the data. Emergency Condition Display Panel 1 2 3 4 17 26 31 14 14 24 34 13 B 15 22 28 12 19 31 10 21 24 29 28 32 15 37 19 Least Squares Means Estimates Panel Estimate Condition Estimate A 21. 625000 17.166670 B 18.250900 24.666670 C 25. 625000 32. 166670 13.333300 Analysis of Variance Sum of Mean Source DF Squares Square F Ratio Model 11 1, 488.3333 135.303 31 . 8360 Error 12 51. 0000 4.250 Prob > F C. Total 23 1, 539.3333 <. effect tests sum of source nparm df squares f ratio prob> F Panel 2 2 218.0833 25 . 6569 <.0001 condition . panel tukey hsd all pairwise comparisons quantile="2.66776," adjusted df="12.0," adjustment="Tukey" difference std error t ratio prob>lt/ Lower 95% Upper 95% A 3.37500 1. 030776 3.27 0. 0169 0. 6251 6. 12486 ar -4.00600 1.030776 -3. 88 0. 0057 -6.7499 -1. 25014 -7. 37500 1.030776 -7. 15 <. test the significance of display panel effects with a=".05." f="25.6569," p-value=".0001;" reject ho emergency condition make pairwise comparisons panels b and c by using tukey simultaneous percent confidence intervals. your answers to decimal places. negative amounts should be indicated minus sign. ha ub: ja uc hb conditions condence p1p2: u1 p1p4: p2p3: p2p4: p3p4: if which minimizes time required stabilize an does answer depend on why calculate interval for mean>