Question: Please help me answer this question This Question: 4 pts 13 of 14 (9 complete) Lenovo uses the ZX-81 chip in some of its laptop

Please help me answer this question

Please help me answer this question This Question: 4 pts 13 of14 (9 complete) Lenovo uses the ZX-81 chip in some of its

This Question: 4 pts 13 of 14 (9 complete) Lenovo uses the ZX-81 chip in some of its laptop computers. The prices for the chip during the last 12 months were as follows: Month Price Per Chip Month Price Per Chip January $1.80 July $1.80 February $1.61 August $1.83 March $1.60 September $1.60 April $1.85 October $1.57 May $1.90 November $1.62 June $1.95 December $1.75 This exercise contains only part d. With a = 0.1 and the initial forecast for October of $1.78, using exponential smoothing, the forecast for periods 11 and 12 is (round your responses to two decimal places): Month Oct Nov Dec Forecast $1.78 With a = 0.3 and the initial forecast for October of $1.77, using exponential smoothing, the forecast for periods 11 and 12 is (round your responses to two decimal places): Month Oct Nov Dec Forecast $1.77 With a = 0.5 and the initial forecast for October of $1.72, using exponential smoothing, the forecast for periods 11 and 12 is (round your responses to two decimal places): Month Oct Nov DecWith a = 0.1 and the initial forecast for October of $1.78, using exponential smoothing, the forecast for periods 11 and 12 is (round your responses to two decimal places): Month Oct Nov Dec Forecast $1.78 With a = 0.3 and the initial forecast for October of $1.77, using exponential smoothing, the forecast for periods 11 and 12 is (round your responses to two decimal places): Month Oct Nov Dec Forecast $1.77 With a = 0.5 and the initial forecast for October of $1.72, using exponential smoothing, the forecast for periods 11 and 12 is (round your responses to two decimal places): Month Oct Nov Dec Forecast $1.72 Based on the months of October, November, and December, the mean absolute deviation using exponential smoothing where a = 0.1 and the initial forecast for October = $1.78 is $ (round your response to three decimal places). Based on the months of October, November, and December, the mean absolute deviation using exponential smoothing where a = 0.3 and the initial forecast for October = $1.77 is $ (round your response to three decimal places). Based on the months of October, November, and December, the mean absolute deviation using exponential smoothing where a = 0.5 and the initial forecast for October = $1.72 is $ (round your response to three decimal places). Based on the mean absolute deviation, the better forecast is achieved using a =

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