please help me answer this. the answers on the page may not be right

Newton's 2nd Law Equations (4 points) 2 * * = ma T - MKmigEmia th=mg OF - FK= mia Mag - T = Mza 2 2 Fyz - FT = M2 a mag - Mum. g = ( m , tmy ) a Solve for a (2 points) 3 a = mag - MKmig mitmz 10 a= (7.0 kg ) ( 9.8 )- (0:25 ) ( 5,0 kg ) (98 ) 5, 0 ko + 70 kg 4.7 52 3. Three boxes are dragged along as shown on a frictionless surface T, m. m m, F F = 25.0 N, m, = 3.5 kg, m2 = 4.0 kg, my = 5.0 kg, find the acceleration of the system (3 points), and find T, and T2. (3 points each) Hint - draw a FBD of the system to find acceleration, and then of each object to find the tensions System: FBD Newton's 2nd Law Equation EF = ma F = ma X X Objects: All in X-dimension FBD Newton's 2nd Law Equation V LEG F : mi a EFEma F - Tzemia 6 FBD V Newton's 2nd Law Equation M2 F = ma T 2 - TEMza L FBD V Newton's 2nd Law Equation EF = Ma V T . = M30 Find a, T, and T2 25.0 N FIma ( 3.5 + 4.0 * 5, 0 ) - 2 5 6 T, = M30 ( 5. OD ( 2 3 0 ) - IO N K - T2 = Min 12 T 2 = ( 25. 20 - ( 3.5 kg ) ( 2 3 2 ) = 18 N 4