Please help me with the following code in Scheme language:

Lambda expressions 3. Functions declared using define can be expressed as the lambda special form. That is, (define (f x) ) is the same as (define f (lambda (x) )) Lambda forms can be used to return anonymous functions. Anonymous functions have a number of important applications in Scheme. For example, here is a function apply-two-unary that returns an anonymous procedure bound to two unary procedures f and g. This anonymous function takes x as an argument. (define (apply-two-unary f g) (lambda (x) (f (g x)))) (a) Write a procedure binary-plus returning a lambda expression. The procedure binary-plus takes two arguments and adds them together. It should work like, (define plus5 (binary-plus 5)) (plus5 7) produces 12. (b) Write a procedure to compute trinary-plus returning nested lambda expressions. The procedure trinary-plus takes three arguments and adds them together. (define plus5+4 ((trinary-plus 5) 4)) ; ; (plus5+4 6) produces 15. Lambda expressions 3. Functions declared using define can be expressed as the lambda special form. That is, (define (f x) ) is the same as (define f (lambda (x) )) Lambda forms can be used to return anonymous functions. Anonymous functions have a number of important applications in Scheme. For example, here is a function apply-two-unary that returns an anonymous procedure bound to two unary procedures f and g. This anonymous function takes x as an argument. (define (apply-two-unary f g) (lambda (x) (f (g x)))) (a) Write a procedure binary-plus returning a lambda expression. The procedure binary-plus takes two arguments and adds them together. It should work like, (define plus5 (binary-plus 5)) (plus5 7) produces 12. (b) Write a procedure to compute trinary-plus returning nested lambda expressions. The procedure trinary-plus takes three arguments and adds them together. (define plus5+4 ((trinary-plus 5) 4)) ; ; (plus5+4 6) produces 15