Question: Please Help! This has to be written in MATLAB CODE and I can't figure it out. Any help would be greatly appreciated! Solve the boundary

Please Help! This has to be written in MATLAB CODE and I can't figure it out. Any help would be greatly appreciated!
Solve the boundary value problem y" + 3y + 2y = 0 with boundary conditions y(0) = 0 and (1) = 1 using the finite difference method with a 3 point stencil to evaluate the first and second derivatives on a uniform mesh. Write a matlab code that will take as input the number of segments n and will output y(x). Plot the solution for 2, 4, 8, and 16 segments on the same plot. Using the results for 4, 8, and 16 segments, estimate the convergence rate and exact answer of the value of y(1) using Richardson extrapolation. If the answer for y(1) is -2.39221119117733, make a loglog plot of the absolute error vs. the number of points in the mesh. Calculate the slope of the log of error versus log of mesh spacing using the last two points of the error plot. Does the actual convergence rate agree with what you predicted by Richardson extrapolation? Does it agree with what you expect theoretically? Solve the boundary value problem y" + 3y + 2y = 0 with boundary conditions y(0) = 0 and (1) = 1 using the finite difference method with a 3 point stencil to evaluate the first and second derivatives on a uniform mesh. Write a matlab code that will take as input the number of segments n and will output y(x). Plot the solution for 2, 4, 8, and 16 segments on the same plot. Using the results for 4, 8, and 16 segments, estimate the convergence rate and exact answer of the value of y(1) using Richardson extrapolation. If the answer for y(1) is -2.39221119117733, make a loglog plot of the absolute error vs. the number of points in the mesh. Calculate the slope of the log of error versus log of mesh spacing using the last two points of the error plot. Does the actual convergence rate agree with what you predicted by Richardson extrapolation? Does it agree with what you expect theoretically
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