Please may I have the solution to this question? especially for part j which hints that I should use and integrate an equation for biomass production rate which truthfully, I am not sure how to express. I tried using the yield of biomass and the cell growth expression ln(X/X0) to write it but I eventually failed. May I have the solution to this and all parts of this question, please? Kind Regards

5. E. coli is a facultative anaerobe. It is proposed to grow E. coli on a medium containing glucose as the carbon and energy source. The E. coli strain we will use can produce an intracellular polysaccharide which can be sold. Question 5, h) The yield of E. coli is expected to be 0.5 g DW E. colilg sugar. The amount of intracellular polysaccharide produced is expected to be 0.4g polysaccharide / g DW E. coli. We can only perform one fermentation or set of fermentations per day. We wish to produce 100 kg polysaccharide per day. (h) Estimate the amount of glucose needed to produce 100 kg of polysaccharide. (2 marks) Solution hint: h) use 0.4g polysaccharide/g DW E.coli., which has been given in the question, and find kg Ecoli required for 100 kg product use 0.5 g DW E. coli/g sugar to find kg sugar as product. (250 kg EColi & 500 kg sugar) wwwww Question 5, i) (i) Estimate the volume of medium V that is needed if we use a medium with a glucose concentration of 20 g/L. (2 marks) Solution hint: i) Simply divide amount of sugar obtained in part (h) by the concentration value to find volume. (25 m3) (i) The E.coli has a doubling time of 20 minutes. The medium is inoculated with a DW concentration of 0.001 g E.coli per litre. Estimate the length of the duration of the fermentation, assuming there is no lag phase. (3 marks) Question 5, j Solution hint: j) write equation of biomass production rate integrate the equation and continue finding time by using values obtained from previous parts. (fermentation time = 4.4 hrs)