Question: Please need an answer asap Solve the initial value problem dy dt y = 4e' 4 18e, y(0) - 6 y( t ) = x2
Please need an answer asap

Solve the initial value problem dy dt y = 4e' 4 18e, y(0) - 6 y( t ) = x2 - 4xy + Jx dy - 0 Put the problem in standard form. Find the integrating factor, p(a) = Find y(ac) =. Use C as the unknown constant. Consider the initial value problem y - 5y = 30t + 6et, y(0) = yo (a) Solve the initial value problem. (enter y0 for yo). y(t)= (b) Determine the value of yo that separates solutions that grow positively as t -> co from those that grow negatively. yo =
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