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Given the function g(x) - 4c' + 62 -24, find the first derivative, g'(I). g (I) Notice that g'(x) - 0 when z - 1, that is, g'(1) = 0. Now, we want to know whether there is a local minimum or local maximum at 2 - 1, so we will use the second derivative test. Find the second derivative, g"(x). g' (I ) Evaluate g" (1). g"(1) Based on the sign of this number, does this mean the graph of g( ) is concave up or concave down at [Answer either up or down -- watch your spelling!!] At I = 1 the graph of g( ) is concave Based on the concavity of g (T) at 2 - 1, does this mean that there is a local minimum or local maximum at c = 1? [Answer either minimum or maximum -- watch your spelling!!] At T - 1 there is a local