Question: Please solve for part D) and E) and provide reasoning/understanding 1. For each of the following sets of reactions, describe your reactor system and conditions

Please solve for part D) and E) and provide reasoning/understanding

1. For each of the following sets of reactions, describe your reactor system and conditions to maximize the selectivity to D. Make sketches where necessary to support your choices. The rates are in (mol/L's), and concentrations are in (mol/L). (a) 1 A+B D -TIA-10 exp(-8,000K/T)CACB 2 A+BU -T2A-100 exp(-1,000K/T)CA/CB/2 (b) 1 A+B D 2 A+BU -TIA-100 exp(-1,000K/T)CACB -T2A-106 exp(-8,000K/T)CACB (c) 1 A+B D -TIA-10 exp(-1,000K/T)CACB 2 B+DU -T2B-10 exp(-10,000K/T)CBCD (d) 1 A D (2) DU 3 AU -TIA-4280 exp(-12,000K/T)CA -T2D=10,100 exp(-15,000K/T)CD -T3A 26 exp(-18,800K/T)CA (e) 1 A+B D -TIA=10 exp(-10,000K/T)CACB 12D-20 exp(-2,000K/T)CD 13A-10 exp(-3,000K/T) CACB 2 DA+B 3 A+BU (f) 1 A+BD -TIA-800 exp(-8,000K/T)CACB 2 A+BU -12B=10 exp(-300K/T)CACB 3 D+B U2 -r3D-106 exp(-8,000K/T) CDCB

For each of the following sets of reactions, describe your reactor system and conditions to maximize the selectivity to D. Make sketches where necessary to support your choices. The rates are in (mol/Ls), and concentrations are in (mol/L). (a) 1A+BDr1A=10exp(8,000K/T)CACB (2) A+BUr2A=100exp(1,000K/T)CA1/2CB3/2 (b) 1A+BDr1A=100exp(1,000K/T)CACB (2) A+BUr2A=106exp(8,000K/T)CACB (c) AA+BDr1A=10exp(1,000K/T)CACB (2) B+DUr2B=109exp(10,000K/T)CBCD (d) (1) ADr1A=4280exp(12,000K/T)CA (2) DU1r2D=10,100exp(15,000K/T)CD (3) AU2r3A=26exp(18,800K/T)CA (e) 1 A A+BDr1A=109exp(10,000K/T)CACB (2) DA+Br2D=20exp(2,000K/T)CD (3) A+BUr3A=103exp(3,000K/T)CACB (f) (1) A+BDr1A=800exp(8,000K/T)CACB (2) A+BU1r2B=10exp(300K/T)CACB (3) D+BU2r3D=106exp(8,000K/T)CDCBB For each of the following sets of reactions, describe your reactor system and conditions to maximize the selectivity to D. Make sketches where necessary to support your choices. The rates are in (mol/Ls), and concentrations are in (mol/L). (a) 1A+BDr1A=10exp(8,000K/T)CACB (2) A+BUr2A=100exp(1,000K/T)CA1/2CB3/2 (b) 1A+BDr1A=100exp(1,000K/T)CACB (2) A+BUr2A=106exp(8,000K/T)CACB (c) AA+BDr1A=10exp(1,000K/T)CACB (2) B+DUr2B=109exp(10,000K/T)CBCD (d) (1) ADr1A=4280exp(12,000K/T)CA (2) DU1r2D=10,100exp(15,000K/T)CD (3) AU2r3A=26exp(18,800K/T)CA (e) 1 A A+BDr1A=109exp(10,000K/T)CACB (2) DA+Br2D=20exp(2,000K/T)CD (3) A+BUr3A=103exp(3,000K/T)CACB (f) (1) A+BDr1A=800exp(8,000K/T)CACB (2) A+BU1r2B=10exp(300K/T)CACB (3) D+BU2r3D=106exp(8,000K/T)CDCBB

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