Question: Point charges q = 54 C and q2 =-72 C are placed a distance a = 2.1 m apart. A third charge q3 =

Point charges q = 54 C and q2 =-72 C are placed a distance a = 2.1 m apart. A third charge q3 =

Point charges q = 54 C and q2 =-72 C are placed a distance a = 2.1 m apart. A third charge q3 = 27 C is placed between and g a distance b= 0.7 m away from 9. Hint a) What is the force on q, due to both q2 and q3? FA b) What is the force on 43 due to both 91 and 92? Fas = A c) Where can q3 be placed so that the net force on it due to the two othe 93 charges is zero (F = 0 N)? O other side of q2 directly opposite from q1 O other side of q1 directly opposite from q2 between q1 and q2 d) Find the value for b that corresponds to (F= ON). 91 93 b a 92 X

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a To find the force on q1 due to both q2 and q3 we need to calculate the individual forces F1 and F2 acting on q1 from q2 and q3 respectively and then ... View full answer

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