Question: post optimal analysis solve part b only Example B: Consider the following LP: Maximize z = 6X1 + 4x2 Subject to x1 + x2 4

post optimal analysis solve part b only

Example B: Consider the following LP: Maximize z = 6X1 + 4x2 Subject to x1 + x2 4 (multiplied by (-1): -2x1 - x2 0 Optimal tableau (using generalized simplex method): BV X1 X2 S1 S2 RHS Z 0 2 6 0 60 S2 0 1 2 1 16 X1 1 1 1 0 10 Find how does each of the following scenarios affect the current optimal (and feasible) solution: a. Change the value of c1 to be 2. (Answer: the current solution becomes not optimal, new z=40) b. Change the value of a12 to be 0.5 (LHS of x2 in constraint 1). (Answer: the current solution becomes not optimal, new z=80) c. Add a new variable X3: C3 = 3, 013 =-2, 223 = 5 (Answer: the current solution becomes not optimal, new z=300) + this only

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