Question: Precalculus tan(x) + cot(x) = 2 csc (2x) i have the answer but could you please explain each step thoroughly as i am stuck

Precalculus tan(x) + cot(x) = 2 csc (2x) i have the answer

Precalculus tan(x) + cot(x) = 2 csc (2x) i have the answer but could you please explain each step thoroughly as i am stuck on this question and how did it get there. 2/sin2x2 csc (2x)

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