Question: An interior continuous beam shown in figure below carries its own weight plus an additional uniform service dead load of 0.5 k/ft and a

An interior continuous beam shown in figure below carries its own weight plus an additional uniform service dead load of 0.5 k/ft and a uniform service live load of 1.2 k/ft. Design the beam for positive moment (between supports, B and D) and negative moments (at intermediate support; C). Draw the design cross-sections and the elevation of the beam showing the reinforcement location. (Use drafting software for design drawings) Material Properties: Concrete Strength = 5000 psi, normal weight concrete: Grade 60 steel. A D 26 ft 26 ft Note: 1. Service load = unfactored load 2. While estimating the design moments, one should consider the live load placements to generate maximum positive and negative moments. 3. You can use RISA to do structural analysis. for moment of inertia of beams, you can use 0.4 Igross Problem 2: In an oil refining plant, a simply supported beam with U-shape cross section supports a 10 in. diameter pipe carrying crude material. The beam spans a distance of 24 ft. The beam is subjected to a service deadload of 1.4 k/ft (not including self-weight of the beam) and service live load of 1 k/ft. Design the reinforcement needed in the beam support the load. Draw the design cross- section (Use drafting software for design drawings). Material properties: 4000 psi concrete; Grade 60 steel 10 in. pipe U beam greater than 20
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To design the beam and determine the reinforcement we need to calculate positive and negative moments and use these for reinforcement design Heres a stepbystep guide for each problem Problem 1 Assumptions and Given Data Concrete Strength 5000 psi Steel Grade Grade 60 Span 26 ft between supports Service Dead Load 05 kft Live Load 12 kft Steps 1 Calculate Factored Loads Dead Load wd 05 textkft Live Load wl 12 textkft Factored Load wu 12wd 16wl 1205 1612 06 192 252 textkft 2 Calculate Moments For maximum positive moment ... View full answer
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