Question: Problem 2 : The double fixed - end beam in Figure 2 . 1 must sustain a design ultimate distributed torsional load of t =

Problem 2:
The double fixed-end beam in Figure 2.1 must sustain a design ultimate distributed torsional load of t=(4.5+0.05x)kNmm along the span (due to the eccentric loading), in addition to the superimposed dead load (30+0.1y)kNm(self-weight not included) and live load (25+0.1x)kNm. Take the density of RC as 24.5kNm3 and assume mild exposure conditions.
Material properties:
fcu=30MPa;
fy=500MPa;
fyv=250MPa
Figure 3: The double fixed-end beam
The cross section of the beam is rectangular and shown in Figure 2.2. The flexural design results indicate that the area of tension reinforcement needed at the support is As=2500mm2 and the tension reinforcement needed at the midspan is As=1300mm2.
a) Determine the shear force for the beam in Figure 2.1 and draw the shear force envelop.
b) Figure 2.3 shows the torsional moment diagram of the fixed end bean in Figure 2.1. Design the section for shear and torsion.
c) Design the beam for serviceability limit state (SLS). Determine a suitable arrangement for required reinforcement and sketch the steel layout.
Hint: For the seek of simplicity, you don't need to check the deflection of the beam.
Figure 2.2. Rectangular section and its material properties
Figure 2.3: Torsional moment diagram of the beam
Problem 2 : The double fixed - end beam in Figure

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