Problem 5. (3 points) Remaining time: 70:58 (min:sec) You read an online article which states that 42% of Canadian adults regularly take a daily multivitamin. You claim that the actual percentage is different from what the article states. You take a random sample of 89 Canadian adults and find that 35 of them regularly take a daily multivitamin. Use this information to answer the questions below. a. Suppose you wish to perform a hypothesis test of your claim. Select the most appropriate null and alternative hypotheses for this hypothesis test. OA. Ho : p = 0.42 Ha : p # 0.42 B. Ho : M # 0.42 Ha : M = 0.42 OC. Ho : p # 0.42 Ha : p = 0.42 D. Ho : p # 0.42 Ha : p = 0.42 OE. Ho : x = 0.42 Ha : x # 0.42 OF. Ho : M = 0.42 Ha : M + 0.42 OG. Ho : x / 0.42 Ha : x = 0.42 OH. Ho : p = 0.42 Ha : p # 0.42 b. To assess your hypotheses, you wish to compute a bootstrap-based confidence interval from your sample. Which of the following uses of the quantile() function would produce the correct interval bounds for a 92% bootstrap-based confidence interval? A. c(quantile(B$mean, 0.04), quantile(B$mean, 0.92)) B. c(quantile(B$mean, 0.08), quantile(B$mean, 0.92)) O C. c(quantile(B$mean, 0.02), quantile(B$mean, 0.98)) D. c(quantile(B$mean, 0.04), quantile(B$mean, 0.96)) c. After performing the bootstrap, you use it to compute a 92% confidence interval of (0.30126, 0.48526). What conclusion can be made based on this interval? Because the null value of ? captured by the confidence interval, we should ? Ho and conclude that the proportion of Canadian adults who regularly take a daily multivitamin is ? from what is stated in the article. preview answers