Question: Problem 5-15 (Static) Here is a network with the activity times shown in days: a. Find the critical path. A) A-B-D-E-G B) A-C-D-F-G C) A-C-D-E-G
Problem 5-15 (Static)
Here is a network with the activity times shown in days:

a. Find the critical path.
A) A-B-D-E-G
B) A-C-D-F-G
C) A-C-D-E-G
D) A-B-D-F-G
The following table shows the normal times and the crash times, along with the associated costs for each activity.
| ACTIVITY | NORMAL TIME | CRASH TIME | NORMAL COST | CRASH COST | ||||||||||
| A | 7 | 6 | $ | 7,000 | $ | 8,000 | ||||||||
| B | 3 | 2 | 5,000 | 7,000 | ||||||||||
| C | 4 | 3 | 9,000 | 10,200 | ||||||||||
| D | 5 | 4 | 3,000 | 4,500 | ||||||||||
| E | 2 | 1 | 2,000 | 3,000 | ||||||||||
| F | 4 | 2 | 4,000 | 7,000 | ||||||||||
| G | 5 | 4 | 5,000 | 8,000 | ||||||||||
b-1. If the project is to be shortened by four days, which activities, in order of reduction, would be shortened?
- A) A, F, D (or E)
- B) A, C, D (or F), F (or D)
- C) C, F (or E), D (or E)
- D) E, A
b-2. Find the resulting cost to crash. Resulting cost to crash _______
B(3) D(5) F(4) A(7) G(5 (C(4) E(2)Step by Step Solution
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