problem number 4 (question suppoed to say repeat problem 3). Program is in octave

2. Repeat problem 1 using the secant method with the same tolerance. 3. The nonlinear equation 3-6x +0.15 sin(200x) = 0 has a root in the interval (0.5, 1.0). (a) Use the bisection method to find the root with tolerance e=0.0001. (b) Use the secant method to find the root with tolerance e=0.0001. (c) Compare the convergence of the two methods for this equation. How can you explain the performance of the secant method? Hint, consider the graph of the function near the root. 4. Repeat problem 4 with the nonlinear equation (3x - 4)' = 0 which clearly has the solution x = 4/3. Use the initial interval (1.0, 1.5] and tolerance = 0.0001. Explain the performance of each method