Problem: Two capacitors are made of parallel plates. Capacitor $1$ has a plate separation,

d$,$ and plate area A$.$ Capacitor $2$ has a plate separation, $4$d$,$ and plate area A$/2.$ If the

capacitors have the same potential difference dV between their plates, what is the

charge, Q$1,$ on the capacitor $1$ compared to Q$2$ on the capacitor $2?$ Note that dV means

delta V $($V is a potential difference$).$

Q$1=$ Q$2$

Q$1=(1/2)*$Q$2$

Q$1=(1/8)*$Q$2$

Q$1=4*$Q$2$

Q$1=8*$Q$2$