Question: Prove: if Ax = d, x > 0 (*) ( there is a viable solution then min Li-w; S. a Ax + w = d

Prove: if Ax = d, x > 0 (*) ( there

Prove: if Ax = d, x > 0 (*) ( there is a viable solution then min Li-w; S. a Ax + w = d X, w > 0 Where w Wm) there is an optimal solution 0 with w Oln addition, also prove that the optimal viable solution defines a basic viable solution of (*). Also prove that if (*) there is no viable solution so the LPP has an optimal value > 0 = (wi, Prove: if Ax = d, x > 0 (*) ( there is a viable solution then min Li-w; S. a Ax + w = d X, w > 0 Where w Wm) there is an optimal solution 0 with w Oln addition, also prove that the optimal viable solution defines a basic viable solution of (*). Also prove that if (*) there is no viable solution so the LPP has an optimal value > 0 = (wi

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