Question: Prove that for all integers m > 1, [log3 (3m)] = log3 (3m + 1)] = [log3 (3m + 2)]. %3D

Prove that for all integers m > 1, [log3 (3m)] = log3

Prove that for all integers m > 1, [log3 (3m)] = log3 (3m + 1)] = [log3 (3m + 2)]. %3D

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