Question: Prove that for every NFA N, there is an NFA N' with no epsilon transitions.. In this problem you will prove that e-transitions are merely

 Prove that for every NFA N, there is an NFA N' Prove that for every NFA N, there is an NFA N' with no epsilon transitions..

In this problem you will prove that e-transitions are merely "syntactic sugar" that makes writing NFAs easier, but e-transitions are not necessary, not even to help reduce the number of states needed. Prove that for every NFA no e-transitions such that (Q... s. F), there is an NFA N'-Q.. .s.P) with L(N'). Note that N' should have the same state set as L(N )

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