Provide a structure for the compound C6H16N2 using the given information. IR: 3281cm1 'H NMR: 61.1(8H,t,J=7Hz),82.66(4H,q,J=7Hz),82.83(4H,s). (Hint: The triplet at 8I.I conceals another broad resonance that contributes to the integral.) Provide a structure for the given compound. molecular mass 101: IR: 3397,3200,1655,1622cm4 13 C NMR: 27.5,838.0 (weak), 180.5 (weak). IR: 1740cm1 An optically inactive mixture A(C8H10O4) can be resolved into enantiomers and has the given NMR spectra. - 13C NMR: 813.5,841.2,8177.9 - 'H NMR: 81.13(6H2d,J=7Hz);82.65(2H, quartet, J=7H2);89.9(2H,broad s, disappears after D, O shake ) A. Draw either enantiomer. Use wedge and dach bonds, including for arry H atoms on a chirality center. B. Give the smicture for an isomer of misture A that has a melting point that is appreciably different frum that of mitnure A yet NMRR spectra that are almest identical to those of mixture A. Use wedge and dash bonds, inchuding for any H atoms on a chirality center