Question: Pt' | Ag | AgCl | Clag) (KCI sat d) || Pb2+ | Pb(Hg) | Hg |Pt The two reduction half cell reactions: 2AgCl(s) +

Pt' | Ag | AgCl | Clag) (KCI sat d) || Pb2+ | Pb(Hg) | Hg |Pt The two reduction half cell reactions: 2AgCl(s) + 2e- = 2Ag(s) + 2Cl", sat'd KCI E = 0.199 V Pb2+ + 2e- - Pb(Hg) E = -0.1205 V If the concentration of the doubly-charged lead ion is 55.6 uM, what is the new cell potential

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