python no Create or returnso i used removebut why the second one go wrong

Complete the remove_even_multiples () function that takes two parameters: 1. An integer list numbers_list. 2. An integer multiple_of. The function should remove all integer elements in numbers_list that are even and multiples of the parameter multiple_of. Note that this function is altering the parameter list numbers_list. It does not create or return a new list. Some examples of the function being used are shown below. For example: Test Result numbers_list = [1, 5, 23, 3, 6, 17, 9, 18] Before: (1, 5, 23, 3, 6, 17, 9, 18] print("Before:", numbers_list) After: [1, 5, 23, 3, 17, 9] remove_even_multiples (numbers_list, 3) print("After:", numbers_list) The function should remove all integer elements in numbers_list that are even and multiples of the parameter multiple_of. Note that this function is altering the parameter list numbers_list. It does no create or return a new list. Some examples of the function being used are shown below. For example: Test Result numbers_list = [1, 5, 23, 3, 6, 17, 9, 18] Before: [1, 5, 23, 3, 6, 17, 9, 18] print("Before:", numbers_list) After: [1, 5, 23, 3, 17, 9] remove_even_multiples (numbers_list, 3) print("After:", numbers_list) Before: (10, 20, 30, 50, 5430] After: 0 numbers_list = [10, 20, 30, 50, 5430] print("Before:", numbers_list) remove_even_multiples(numbers_list, 5) print("After:", numbers_list) Answer: (penalty regime: 0 %) Reset answer om sin 1 def remove_even_multiples (numbers_list, multiple_of): 2 X = int(multiple_of) 3 for element in numbers_list: if element % 2 0 and element % x == 0: 5 numbers_list.remove(element) Precheck Check Expected Got 3, 3, 6, 17, 9, 18] Before: [1, 5, 23, 3, 6, 17, 9, 18]- Before: [1, 5, 23, 3, 6, 17, 9, 18) - s_list) After: [1, 5, 23, 3, 17, 9] After: [1, 5, 23, 3, 17, 9] umbers_list, 3) list) Before: [10, 20, 30, 50, 5430] After: [] X 30, 50, 5430] s_list) umbers_list, 5) _list) Before: [10, 20, 30, 50, 5430] After: [20, 50] earn any marks. Try again