Question: Q1. Part a) A memory is byte addressable and has a 18-bit address. All the addresses are valid. What is the total size of the

Q1.

Part a) A memory is byte addressable and has a 18-bit address. All the addresses are valid. What is the total size of the memory?

Part b) A memory is byte addressable and has a total size of 20,480 bytes (20 KB). What is the smallest address size that can be used for this memory?

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer

Step: 1 Unlock blur-text-image

Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock

Step: 3 Unlock

Students Have Also Explored These Related Databases Questions!

Part a ) A memory is byte addressable and has a 1 8 - bit address. All the addresses are valid. What is the total size of the memory? Part b ) A memory is byte addressable and has a total size of 1 7...

QUESTION 3 . ( 1 0 points ) Part a ) A memory is byte addressable and has a 1 8 - bit address. All the addresses are valid. What is the total size of the memory? Part b ) A memory is byte addressable...

III. Consider a virtual address system with the following parameters .The memory is byte addressable Virtual addresses are 16 bits wide. Physical addresses are 15 bits wide. . The page size is 512...

III. Consider a virtual address system with the following parameters. The memory is byte addressable. . Virtual addresses are 15 bits wide. . Physical addresses are 13 bits wide. The page size is 128...

III. Consider a virtual address system with the following parameters. The memory is byte addressable. Virtual addresses are 16 bits wide. . Physical addresses are 15 bits wide .The page size is 512...

5. Memory hierarchy: Cache design and analysis (13 points) The memory is byte addressable. Memory accesses are to 1-byte words. Physical addresses are 8 bits wide. The cache is 2-way set associative,...

The memory is byte addressable. Memory accesses are to 4-byte words. Virtual addresses are 20 bits wide. Physical addresses are 16 bits wide. The page size is 4096 bytes. The TLB is 4-way set...

The Cache and main memory details for a direct cache mapping function are as follows: Cache size is 2 5 6 K Byte, Cache line size is 3 2 Bytes, Main memory size is 6 4 M Bytes. Main Memory is Byte...

Assume the following of a simple memory system The memory is byte addressable Memory accesses are 1 - byte 1 4 - bit virtual addresses, 1 2 - bit physical address, page size = 6 4 bytes TLB: 4 - way...

Simulate a small virtual memory system with TLB and L1 D-cache with following assumptions: The memory is byte addressable Memory accesses are to 1-byte words (not 4-byte words) Virtual addresses are...

For the circuit in Fig. 7.88, if v = 10e 4t V and i = 0.2e 4t A, t > 0 (a) Find R and C. (b) Determine the time constant. (c) Calculate the initial energy in the capacitor. (d) -Obtain the time it...

What is the Net Income for the Month ended June 30, 2004? What is the Revenue for the Month ended June 30, 2004? What is the Total Expense for the Month ended June 30, 2004? What is the Adjusted...

Here are data on two stocks, both of which have discount rates of 1 4 % : Stock AStock BReturn on equity 1 4 % 1 0 % Earnings per share$ 1 . 5 0 $ 1 . 4 0 Dividends per share$ 1 . 2 0 $ 1 . 2 0 What...

The sandwich maker of the EE-Cole-Eye Sandwich Truck was just fired (for a reason described below) and EE-Cole-Eye needs to find a replacement. They want to make sure that the replacement is fast...

Define self-esteem and discuss its impact on your life.

Discuss how selfesteem is developed.

Identify the characteristics of people with low and high selfesteem.